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Let us multiply ab by itself using Polynomial Multiplication (ab) (ab) = a2 2ab b2 Now take that result and multiply by ab again (a 2 2ab b 2 ) (ab) = a3 3a2b 3ab2 b3 And again (a 3 3a 2 b 3ab 2 b 3 ) (ab) = a4 4a3b 6a2b2 4ab3 b44 Binomial Expansions 41 Pascal's riTangle The expansion of (ax)2 is (ax)2 = a2 2axx2 Hence, (ax)3 = (ax)(ax)2 = (ax)(a2 2axx2) = a3 (12)a 2x(21)ax x 3= a3 3a2x3ax2 x urther,F (ax)4 = (ax)(ax)4 = (ax)(a3 3a2x3ax2 x3) = a4 (13)a3x(33)a2x2 (31)ax3 x4 = a4 4a3x6a2x2 4ax3 x4 In general we see that the coe cients of (a x)n come from the nth row of Pascal'sWhat are the coefficients for the binomial expansion of (a b)3? Algebra Expansion And Factorisation (a+b+c)^3 expansion

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